Consider the exponential function f(x) = 2(3x) and its graph. On a coordinate plane, an exponential function approaches y = 0 in
Question
Consider the exponential function f(x) = 2(3x) and its graph.
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases in quadrant 1. The equation of the function is y = f (x). The function crosses the y-axis at (0, 2).
The initial value of the function is.
The base of the function is.
The function shows exponential
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2022-01-07T05:37:25+00:00
2022-01-07T05:37:25+00:00 2 Answers
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Answer:
The initial value of the function is 2
The base of the function is 3
The function shows exponential growth
Step-by-step explanation:
f(x) = 2(3^x)
Exponential functions are those with the following equation:
y = a*b^x
where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.
a is the y-intercept and b is the base.
The initial value of the function is the same as the y-intercept
If a is positive, the function growth. If a is negative, the function decay
Answer:
The initial value of the function is 2
The base of the function is 3
The function shows exponential growth
Step-by-step explanation: