## Consider the exponential function f(x) = 2(3x) and its graph. On a coordinate plane, an exponential function approaches y = 0 in

Question

Consider the exponential function f(x) = 2(3x) and its graph.

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases in quadrant 1. The equation of the function is y = f (x). The function crosses the y-axis at (0, 2).

The initial value of the function is.

The base of the function is.

The function shows exponential

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2022-01-07T05:37:25+00:00
2022-01-07T05:37:25+00:00 2 Answers
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## Answers ( )

Answer:The initial value of the function is

2The base of the function is

3The function shows exponential

growthStep-by-step explanation:f(x) = 2(3^x)

Exponential functions are those with the following equation:

y = a*b^x

where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.

ais the y-intercept andbis the base.The initial value of the function is the same as the y-intercept

If

ais positive, the function growth. Ifais negative, the function decayAnswer:The initial value of the function is 2

The base of the function is 3

The function shows exponential growth

Step-by-step explanation: