Consider the exponential function f(x) = 2(3x) and its graph. On a coordinate plane, an exponential function approaches y = 0 in

Question

Consider the exponential function f(x) = 2(3x) and its graph.

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases in quadrant 1. The equation of the function is y = f (x). The function crosses the y-axis at (0, 2).
The initial value of the function is.

The base of the function is.

The function shows exponential

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Eva 3 weeks 2022-01-07T05:37:25+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-07T05:38:25+00:00

    Answer:

    The initial value of the function is 2

    The base of the function is 3

    The function shows exponential growth

    Step-by-step explanation:

    f(x) = 2(3^x)

    Exponential functions are those with the following equation:

    y = a*b^x

    where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.

    a is the y-intercept and b is the base.

    The initial value of the function is the same as the y-intercept

    If a is positive, the function growth. If a is negative, the function decay

    0
    2022-01-07T05:39:17+00:00

    Answer:

    The initial value of the function is 2

    The base of the function is 3

    The function shows exponential growth

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )