Consider the line 4x – 2y=-5. Find the equation of the line that is perpendicular to this line and passes through the point (-1, -2).<

Question

Consider the line 4x – 2y=-5.
Find the equation of the line that is perpendicular to this line and passes through the point (-1, -2).

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Faith 2 weeks 2021-11-20T11:15:47+00:00 1 Answer 0 views 0

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    2021-11-20T11:17:40+00:00

    Answer:

    2y+x = -5

    Step-by-step explanation:

    From 4x – 2y = -5

    -2y = -4x-5

    Divide through by -2

    y = 2x + 5/2 comparing with y = mx +c

    m1= 2

    For perpendicularity: m1m2 = -1

    m2 = -1/2

    equation passing through (-1,-2) and perpendicular to 4x-2y =-5 is:

    y-y1 = m2(x-x1)

    y-(-2) = -1/2(x-(-1)) = -1/2(x+1)

    y+2 = -x/2 – 1/2

    Multiply through by 2

    2y + 4 = -x – 1

    2y=-x-1-4

    2y=-x-5

    2y+x = -5

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