(x+d)(x+e)=x^2+fx+33 In the equation above, d, e, and f are positive constants.Which of the following are possible integer values of f

Question

(x+d)(x+e)=x^2+fx+33
In the equation above, d, e, and f are positive constants.Which of the following are possible integer values of f?
a) f= 0 or 1
b) f= 1 or 33
c) f= 2 or 16.5
d) f= 14 or 34

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Kaylee 3 weeks 2021-09-28T04:48:36+00:00 1 Answer 0

Answers ( )

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    2021-09-28T04:50:31+00:00

    Answer:

    f=14 or f=34

    Step-by-step explanation:

    (x+d)(x+e) =x^2 +fx+33, d, e, f>0

    x^2 +xe+dx+de=x^2+fx+33

    x^2+(e+d)x+de=x^2 +fx+33 that

    e+d=f and d*e=33, d=33/e

    e+33/e=f

    33=1*33 or 33=3*11

    If e=1,d=33 then f=34

    If e=3*,d=11, then f=14

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