Determine the required value of the missing probability to make the distribution a discrete probability distribution. x ​P(x) 3 0.170.17 4 ​

Question

Determine the required value of the missing probability to make the distribution a discrete probability distribution. x ​P(x) 3 0.170.17 4 ​? 5 0.350.35 6 0.270.27 ​P(4) = nothing ​(Type an integer or a​ decimal.)

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Ruby 6 hours 2021-09-15T04:00:39+00:00 1 Answer 0

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    2021-09-15T04:02:29+00:00

    Answer:

    The probability of X = 4 is 0.21.

    Step-by-step explanation:

    The discrete probability distribution of the random variable X is:

       x:   3   |  4     |   5    |   6

    P (x): 0.17 | ___ | 0.35 | 0.27

    The properties of a probability distribution are:

    • 0 ≤ P (X) ≤ 1
    • ∑ P (X) = 1

    All the probability value are more than 0 and less than 1.

    Compute the probability for X = 4 as follows:

    \sum P(X)=1\\P(X=3)+P(X=4)+P(X=5)+P(X=6)=1\\0.17+a+0.35+0.27=1\\0.79+a=1\\a=1-0.79\\a=0.21

    Thus, the probability of X = 4 is 0.21.

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45:7+7-4:2-5:5*4+35:2 =? ( )