Determine the vertex of y = 3x^2- 6x – 5.

Question

Determine the vertex of y = 3x^2- 6x – 5.

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Faith 1 month 2021-10-26T17:13:24+00:00 1 Answer 0 views 0

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    2021-10-26T17:14:26+00:00

    Answer:

    Consider the vertex form of a parabola. Substitute the values of a a and b b into the formula d=b2a d = b 2 a . Simplify the right side. Cancel the common factor of 6 6 and 2 2 .

    Step-by-step explanation:

    the x value of the vertex in ax^2+bx+c is -b/2a

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub back

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1y=2

    the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1y=2vertex is (1,2)

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45:7+7-4:2-5:5*4+35:2 =? ( )