During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 dB with a standard deviation of 8 dB. Without assum

Question

During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 dB with a standard deviation of 8 dB. Without assuming a normal distribution, find the minimum percentage of noise level readings within 3 standard deviations of the mean. (Round your answer to 2 decimal places.)Minimum percentage____%

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Piper 2 weeks 2021-09-11T05:06:07+00:00 1 Answer 0

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    2021-09-11T05:07:11+00:00

    Answer:

    Minimum percentage = 88.89%

    Step-by-step explanation:

    We are given the following in the question:

    Mean, μ = 95 dB

    Standard Deviation, σ = 8 dB

    Chebyshev’s rule:

    • According to this rule atleast 1 - \dfrac{1}{k^2} percent of data lies within k standard deviation of mean.

    We have to find the minimum percent of data lying within 3 standard deviations of the mean.

    Putting values, we get,

    1 - \dfrac{1}{(3)^2} = 88.89\%

    Thus, minimum 88.895 of data lies within 3 standard deviations of the mean.

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