## Ellen has a movie rental card worth \$225. After she rents the first movie, the card’s value is \$221.75. After she rents the second movie,

Question

Ellen has a movie rental card worth \$225. After she rents the first movie, the card’s value is \$221.75. After she rents the second movie, its value is \$218.50. After the third rental, the card is worth \$215.25. Assuming the pattern continues, write an equation to define A(n), the amount of money on the card after n rentals. Ellen rents a movie every Saturday night. How many weeks in a row can she afford to rent a movie, using her rental card only?

in progress 0
8 months 2021-10-04T02:26:57+00:00 2 Answers 0 views 0

69 times

Step-by-step explanation:

\$225 – \$221.75 = \$3.25

\$221.75 – \$218.50 = \$3.25

… etc

Therefore pattern is 3.25

Need to find how many times \$3.25 can be taken from \$225

So

\$225/\$3.25 = 69.2 times

69 times (whole number)

2. Answer: She can rent 69 weeks in a row(assuming its counting from the inital value which is 225)

Step-by-step explanation: The equation would be A(n)=225-3.25^(n-1). I think thats the equation, im not sure since it has been a few years since i did these kinds of questions.