f(x) = Square root of quantity x plus nine. ; g(x) = 8x – 13 Find f(g(x)). (1 point)

Question

f(x) = Square root of quantity x plus nine. ; g(x) = 8x – 13 Find f(g(x)). (1 point)

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Adalynn 2 weeks 2021-11-18T05:36:52+00:00 1 Answer 0 views 0

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    2021-11-18T05:38:36+00:00

    f(g(x)) = 2\sqrt{2x-1}

    Solution:

    Given that,

    f(x) = \sqrt{x+9}\\\\g(x) = 8x - 13

    We have to find f(g(x))

    Which means, substitute g(x) value in place of x in f(x)

    Therefore,

    f(g(x)) = \sqrt{8x - 13 + 9}\\\\Simplify\\\\f(g(x)) = \sqrt{8x -4}\\\\Take\ common\ factor\ out\\\\f(g(x)) = \sqrt{4(2x-1)}\\\\f(g(x)) = 2\sqrt{2x-1}

    Thus f(g(x)) is found

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