Farmer Fran has 38 barnyard animals consisting of only chickens and goats. If these animals have 116 legs how many of each type of animal ar

Question

Farmer Fran has 38 barnyard animals consisting of only chickens and goats. If these animals have 116 legs how many of each type of animal are there?

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Lyla 3 months 2021-10-19T21:10:38+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-19T21:12:03+00:00

    Answer:

    chickens is represented by C, and the number of goats is G.

    C=18

    G=20

    Total of Animals equation:

    a)C+ G = 38

    Total of legs equation (since chickens have 2 legs and goats have 4 ):

    b)2C + 4 G =116

    If we multiply a) by 2 and subtract a) from b).

    2C + 4 G =116

    2C + 2 G =76

    _________

    2G = 40

    Solving for G:

    G = 40/2

    G= 20

    Replacing the value of G on any equation:

    a) C+ (20) =38

    Solving for C

    C =38-20

    C=18

    There are 20 goats and 18 chickens.

    0
    2021-10-19T21:12:29+00:00

    Answer: There are 20 goats and 18 chikens.

    Step-by-step explanation:

    Hi, to answer this question we have to write a system of equations:

    If the number of chickens is represented by C, and the number of goats is G.

    Total of Animals equation:

    a)C+ G = 38

    Total of legs equation (since chickens have 2 legs and goats have 4 ):

    b)2C + 4 G =116

    If we multiply a) by 2 and subtract a) from b).

    2C + 4 G =116


    2C + 2 G =76

    _________

    2G = 40

    • Solving for G:

    G = 40/2

    G= 20

    Replacing the value of G on any equation:

    a) C+ (20) =38

    • Solving for C

    C =38-20

    C=18

    There are 20 goats and 18 chickens.


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