Find all integers $n$ such that the quadratic $7x^2 + nx – 11$ can be expressed as the product of two linear factors with integer coefficien

Question

Find all integers $n$ such that the quadratic $7x^2 + nx – 11$ can be expressed as the product of two linear factors with integer coefficients.

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Charlie 7 days 2021-09-08T06:13:58+00:00 1 Answer 0

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    2021-09-08T06:15:53+00:00

    Answer:

    The all integer values of n are -76, -4, 4, 76

    Step-by-step explanation:

    ∵ The factors of 7 are 1 and 7

    ∵ The factors of 11 are 1 and 11

    – The last term of the quadratic is negative, that means the two

        linear factors have different middle sign

    ∴ The factors are (7x ± 1)(x ± 11) OR (7x ± 11)(x ± 1)

    Let us take one by one

    The middle term of the quadratic is the sum of the product of nears and ext-reams

    In (7x + 1)(x – 11)

    ∵ The product of ext-reams is 7x × -11 = -77x

    ∵ The product of nears is 1 × x = x

    ∵ Their sum is -77x + x = -76x

    ∴ n = -76

    In (7x – 1)(x + 11)

    ∵ The product of ext-reams is 7x × 11 = 77x

    ∵ The product of nears is -1 × x = -x

    ∵ Their sum is 77x + -x = 76x

    ∴ n = 76

    In (7x + 11)(x – 1)

    ∵ The product of ext-reams is 7x × -1 = -7x

    ∵ The product of nears is 11 × x = 11x

    ∵ Their sum is -7x + 11x = 4x

    ∴ n = 4

    In (7x – 11)(x + 1)

    ∵ The product of ext-reams is 7x × 1 = 7x

    ∵ The product of nears is -11 × x = -11x

    ∵ Their sum is 7x + -11x = -4x

    ∴ n = -4

    The all integer values of n are -76, -4, 4, 76

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45:7+7-4:2-5:5*4+35:2 =? ( )