Find dydt for the equation below. 7×3+7y3=9

Question

Find dydt for the equation below.

7×3+7y3=9

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Alice 1 week 2021-09-08T01:51:29+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T01:52:45+00:00

    Answer:

    dy/dt = -x^2/y^2  dx/dt

    Step-by-step explanation:

    7x^3 + 7y^3 = 0

    Take the derivative with respect to t

    7 * 3x^2 dx/dt + 7 * 3y^2 dy/dt = 0

    21 x^2 dx/dt +21  y^2 dy/dt =0

    Divide each side by 21

    x^2 dx/dt+ y^2 dy/dt =0

    Subtract x^2 dx/dt from each side

    x^2 dx/dt  – x^2 dx/dt+y^2 dy/dt = -x^2 dx/dt

    y^2 dy/dt = -x^2 dx/dt

    Divide each side by y^2

    y^2 /y^2 dy/dt = -x^2/y^2 dx/dt

    dy/dt = -x^2/y^2  dx/dt

    0
    2021-09-08T01:52:48+00:00

    Answer:

    y=-1

    Step-by-step explanation:

    I thought the unknown space between 7y and 3 was multiplication so here is my work.

    7*3+7y*3

    21+7*-1*3

    =9

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