## Find the arc length parameter along the given curve from the point where t=0 by evaluating the integral s(t)=lv(t)ldt The

Question

Find the arc length parameter along the given curve from the point where t=0 by evaluating the integral s(t)=lv(t)ldt

Then find the length of indicated portion of the curve r(t)= 5costi+5sintj+8tk, where 0<_t<_pi

The arc length parameter along the curve, starting at t=0 is s(t)=____. (Type exact answers, using radicals as needed)

The length of the indicated portion of the curve is L=___. (Type exact answers, using radicals and Pi as needed)

Find the arc length parameter along the given curve from the point where t=0 by evaluating the integral s(t)=lv(t)ldt

Then find the length of indicated portion of the curve r(t)=(2e^tcost)i+(2e^tsint)j-2e^tk, -ln4<_t<_0 s(t)=__ (Type exact answers, using radicals as needed)

The length of rage indicated portion of the curve is __ units. (Type exact answers, using radicals as needed)

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4 weeks 2021-09-19T03:17:02+00:00 1 Answer 0

Step-by-step explanation:

Consider the following curve: where Need to find the arc length parameter and legth of the indicated portion of the curve

Difference with respect to  The formular for arc length of a curve is So, hence the arc length is 7.0443