Find the center and the radius of the circle with the equation . x + 2x + y2 – Zy- 14 = 0) a. center. (1,-1) c. center. (2

Question

Find the center and the radius of the circle with the equation .
x + 2x + y2 – Zy- 14 = 0)
a. center. (1,-1)
c. center. (2,-2)
radius: 4
radius. 14
b. center. (-1,1)
d. center. (-2,2)
radius: 4
radius. 14

in progress 0
Aaliyah 2 weeks 2021-09-11T20:19:58+00:00 1 Answer 0

Answers ( )

    0
    2021-09-11T20:21:17+00:00

    We have been given an equation of circle x^2+2x+y^2-2y-14=0. We are asked to find the center and radius of the circle.

    First of all, we will write equation of circle is standard form (x-h)^2+(y-k)^2=r^2, where center of circle is at point (h,k) and radius is r.

    Let us complete the square for both x and y.

    x^2+2x+y^2-2y-14+14=0+14

    x^2+2x+y^2-2y=14

    Adding half the square of coefficient of x and y term, we will get:

    (\frac{2}{2})^2=1^2=1

    (\frac{-2}{2})^2=(-1)^2=1

    x^2+2x+1+y^2-2y+1=14+1+1

    (x+1)^2+(y-1)^2=16

    (x-(-1))^2+(y-1)^2=4^2

    Therefore, the center of the circle is (-1,1) and radius is 4 units.

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )