Find the equation of the axis of symmetry for this function F(x)= 5x^2 – 3x + 5

Question

Find the equation of the axis of symmetry for this function
F(x)= 5x^2 – 3x + 5

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Vivian 3 months 2021-10-16T03:17:05+00:00 1 Answer 0 views 0

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    2021-10-16T03:18:21+00:00

    Answer:

    x = \frac{3}{10}

    Step-by-step explanation:

    Given a quadratic in standard form, ax² + bx + c : a ≠ 0

    Then the axis of symmetry is a vertical line with equation x = h

    where h is the x- coordinate of the vertex.

    The x- coordinate of the vertex is

    x_{vertex} = – \frac{b}{2a}

    f(x) = 5x² – 3x + 5 ← is in standard form

    with a = 5 and b = – 3, thus

    x_{vertex} = – \frac{-3}{10} = \frac{3}{10}

    Thus the equation of the axis of symmetry is x = \frac{3}{10}

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