Find the solution to the system of equations by using the substitution method Y=4x+1 Y=x+1

Question

Find the solution to the system of equations by using the substitution method
Y=4x+1
Y=x+1

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Parker 2 weeks 2021-09-13T01:06:36+00:00 1 Answer 0

Answers ( )

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    2021-09-13T01:08:21+00:00

    Answer:

    x = 0

    y = 1

    Step-by-step explanation:

    y = 4x + 1 ——-eqn 1

    y = x + 1 ——-eqn 2

    Looking for x, let’s use eqn 1

    y = 4x + 1

    4x = y – 1

    Divide both sides by 4, to get x

    4x/4 = (y – 1) / 4

    x = (y – 1) / 4

    Substitute the value of x into eqn 2

    y = x + 1

    y = (y – 1) / 4 + 1

    LCM = 4

    y =( y – 1 + 4)/4

    y =( y + 3) / 4

    Cross multiply

    y * 4 = y + 3

    4y = y + 3

    4y – y = 3

    3y = 3

    Divide both sides by 3, to get y

    3y / 3 = 3/3

    y = 1

    Substitute y = 1 , into eqn 1

    y = 4x + 1

    1 = 4x + 1

    1 -1 = 4x

    0 = 4x

    Divide both sides by 4, to get x

    0/4 = 4x/4

    0 = x

    x = 0

    Hint, let’s check if the values are correct

    Let’s pick eqn 2

    y = x + 1

    y = 1

    x = 0

    1 = 0 + 1

    1 = 1

    Correct

    Let’s try the eqn 1

    y = 4x + 1

    1 = 4(0) + 1

    1 = 0 + 1

    1 = 1

    Correct too

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