Find the value of the discriminant for 7x^{2} +5x+1=0. Then describe the number and type of roots for the equation.

Question

Find the value of the discriminant for 7x^{2} +5x+1=0. Then describe the number and type of roots for the equation.

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Alice 1 month 2021-10-14T22:57:57+00:00 1 Answer 0 views 0

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    2021-10-14T22:59:51+00:00

    Answer:

    No real roots

    Step-by-step explanation:

    Given

    7x² + 5x + 1 = 0 ← in standard form

    with a = 7, b = 5, c = 1

    To determine the nature of the roots use the discriminant

    Δ = b² – 4ac

    • If b² – 4ac > 0 then roots are real and distinct

    • If b² – 4ac = 0 then roots are real and equal

    • If b² – 4ac < 0 then the roots are not real

    Here

    b² – 4ac = 5² – (4 × 7 × 1) = 25 – 28 = – 3

    Thus the 2 roots are not real

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