find the VERTEX of the parabola f(x) = x^2 – 16x + 63 Question find the VERTEX of the parabola f(x) = x^2 – 16x + 63 in progress 0 Math Rylee 3 weeks 2021-09-09T07:43:58+00:00 2021-09-09T07:43:58+00:00 1 Answer 0

## Answers ( )

Answer:vertex = (8, – 1 )

Step-by-step explanation:Given a parabola in standard form, f(x) = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

= –

f(x) = x² – 16x + 63 ← is in standard form

with a = 1 and b = – 16, thus

= – = 8

Substitute x = 8 into f(x)

f(8) = 8² – 16(8) + 63 = 64 – 128 + 63 = – 1

vertex = (8, – 1 )