Find the zeros (x-intercepts) of the quadractic function y=2/3(3x-2)(3x+6)

Question

Find the zeros (x-intercepts) of the quadractic function y=2/3(3x-2)(3x+6)

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Arianna 6 days 2021-09-12T01:44:39+00:00 1 Answer 0

Answers ( )

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    2021-09-12T01:46:09+00:00

    Answer:

    x = – 2, x = \frac{2}{3}

    Step-by-step explanation:

    T o find the zeros let y = 0, that is

    \frac{2}{3} (3x – 2)(3x + 6) = 0 ← in standard form

    Equate each factor to zero and solve for x

    3x – 2 = 0 ⇒ 3x = 2 ⇒ x = \frac{2}{3}

    3x + 6 = 0 ⇒ 3x = – 6 ⇒ x = – 2

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