For a moving object the force acting on the object varies directly from the objects acceleration when a force of 25 N acts on a certain obje

Question

For a moving object the force acting on the object varies directly from the objects acceleration when a force of 25 N acts on a certain object the acceleration of the object is 5 m/s2 top of two if the force exchange to 10 N what will be the acceleration of the object

in progress 0
Mia 4 weeks 2021-11-07T05:47:39+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-11-07T05:49:35+00:00

    Answer:

    2m/s²

    Step-by-step explanation:

    If for a moving object the force acting on the object varies directly from the objects acceleration, then it can be expressed as:

    F∝a

    F = ka.

    F is the force

    a is the object’s acceleration

    From the expression;

    k is the constant of proportionality

    When an initial force of 25 N acts on the object and the acceleration of the object is 5 m/s², then

    k = 25/5

    k = 5Ns²/m

    If the force exchange to 10 N, the acceleration of the object will be gotten using the relationship above

    F = ka

    Given F = 10N and k = 5Ns²/m

    a = F/k = 10/5

    a = 2m/s²

    The acceleration of the object will be 2m/s²

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )