## Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger two numbers

Question

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger two numbers. What are the three integers?

this was my initial answer to the question:
(x-2), x, (x+2)

4((x+2) + x+ (x-2))=3((x+2)(x)) – 765

4(3x)=3×2+6x-765

4x=x2+2x-255

X2-2x-255=0

X2-17x+15x-255=0

X(x-17)+15(x-17)=0

(x+15)(x-17)=0

(x-17)=0

X=17
however it was sent back to me with:
‘You should end up with 2 values for x. You then need to write the two sets of three integers.’

I am unsure as to what i am supposed to do with this now :/
Thanks

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2 weeks 2022-01-15T03:34:03+00:00 1 Answer 0 views 0

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be:

The condition given is:

Solve this for x as follows:

• If then the value of x is 17.

The odd numbers are:

• If then the value of x is -15.

The odd numbers are:

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).