## Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger two numbers

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger two numbers. What are the three integers?

this was my initial answer to the question:

(x-2), x, (x+2)

4((x+2) + x+ (x-2))=3((x+2)(x)) – 765

4(3x)=3×2+6x-765

4x=x2+2x-255

X2-2x-255=0

X2-17x+15x-255=0

X(x-17)+15(x-17)=0

(x+15)(x-17)=0

(x-17)=0

X=17

however it was sent back to me with:

‘You should end up with 2 values for x. You then need to write the two sets of three integers.’

I am unsure as to what i am supposed to do with this now :/

Thanks

## Answers ( )

Answer:The consecutive odd integers are

(15, 17, 19)or(-17, -15, -13).Step-by-step explanation:Let the three consecutive odd integers be:

The condition given is:

Solve this for

xas follows:xis 17.The odd numbers are:

xis -15.The odd numbers are:

Thus, the consecutive odd integers are

(15, 17, 19)or(-17, -15, -13).