g(x)=\sqrt{x+3}g(x)= x+3 ​ g, left parenthesis, x, right parenthesis, equals, square root of, x, plus, 3, end square ro

Question

g(x)=\sqrt{x+3}g(x)=
x+3

g, left parenthesis, x, right parenthesis, equals, square root of, x, plus, 3, end square root
Determine for each xxx-value whether it is in the domain of ggg or not.

in progress 0
Ella 2 weeks 2021-09-08T16:57:18+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T16:58:53+00:00

    Answer:

    All real values of x such that x\geq-3

    Step-by-step explanation:

    0
    2021-09-08T16:59:03+00:00

    Answer:

    The domain of the function g(x) s the interval [-3,∞)

    x\geq -3

    Step-by-step explanation:

    we have

    g(x)=\sqrt{x+3}

    we know that

    The radicand must be greater than or equal to zero

    so

    x+3\geq 0

    solve for x

    x\geq -3

    The domain is the interval [-3,∞)

    All real numbers greater than or equal to -3

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )