Give the equation of the line through the point (4, 5) with a slope of – 9/2 in slope-intercept form

Question

Give the equation of the line through the point (4, 5) with a slope of – 9/2
in slope-intercept form

in progress 0
Bella 6 days 2021-10-07T14:48:00+00:00 2 Answers 0

Answers ( )

    0
    2021-10-07T14:49:48+00:00

    The required line is 2y = -9x + 26

    Step-by-step explanation:

    Given,

    The point is (x1 ,y1) = (4,5) and

    Slope (m) = \frac{-9}{2}

    Formula

    The equation of a line through point (x1 ,y1) and slope m will be

    \frac{y-y1}{x-x1} = m

    Now, putting the values as (4,5) and \frac{-9}{2} we get,

    \frac{y-5}{x-4} = \frac{-9}{2}

    or, 2(y-5) = -9(x-4) [ by cross multiplication]

    or, 2y – 10 = -9x + 36

    or, 9x + 2y = 26

    or, 2y = -9x + 26

    Here is the equation of the line.

    0
    2021-10-07T14:49:50+00:00

    Answer:

    Step-by-step explanation:

    y – y1 = m(x – x1)

    y – 5 = -9/2*(x – 4)

    y -5  = -9/2x + 9*4/2

    y – 5 = -9x/2 +9*2

    y-5=-9x/2 + 18

    y= -9x/2 + 18 +5

    y= -9x/2 + 23    {y =mx+c}

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )