Given that cosθ=3/5 in quadrant 3, fin sinθ

Question

Given that cosθ=3/5 in quadrant 3, fin sinθ

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Rylee 2 months 2021-09-12T10:17:51+00:00 1 Answer 0 views 0

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    2021-09-12T10:19:15+00:00

    Answer:

    Sin theta =4/5

    Step-by-step explanation:

    Cos theta=base/HYPOTENUSE=3/5

    Hence

    From here we get

    Base=3,HYPOTENUSE =5

    By Pythagoras theorem

    Hypotenuse ²=base²+perp²

    5²=3²+perpendicular²

    25=9+perp²

    Perp²=25-9

    Perp ²=16

    Perp=4(taking sq root on both sides)

    Now

    Sin theta=perp/hyp=4/5

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