## Given that the line y=c-2x is tangent to the curve y^2=kx where c and k are non-zero constants,express k in terms of c

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## Answers ( )

Answer:k = -8c.Step-by-step explanation:y^2 = kx

Find the slope of the tangent by differentiating:

y’ 2y = k

y’ = k / 2y = the slope of the tangent.

The given equation of the tangent is y = -2x + c so the slope = -2.

Therefore k/2y = -2 so k = -4y and

y = -k/4y^2 = kx so k^2/16 = kx giving

x = k/16.Substituting for x and y in y = -2x + c:

-k/4 = -2 k/16 + c

-k/4 = -k/8 + c

c= -k/4 + k/8 =-k/8.So -k = 8c

k = -8c.