Given the equation of the parabola -36y = x^2 The focus of the parabola is

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Given the equation of the parabola -36y = x^2 The focus of the parabola is

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Kennedy 15 hours 2021-10-14T02:33:35+00:00 1 Answer 0

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    2021-10-14T02:35:32+00:00

    (0,-9) or -x2/36,,,, -x2 on top

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45:7+7-4:2-5:5*4+35:2 =? ( )