Given the functions a(x) = 3x − 12 and b(x) = x − 9, find a[b(x)]. PLZ HELPPPPPPPPPP!!!!

Question

Given the functions a(x) = 3x − 12 and b(x) = x − 9, find a[b(x)].

PLZ HELPPPPPPPPPP!!!!

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Evelyn 2 weeks 2021-09-11T00:51:51+00:00 2 Answers 0

Answers ( )

  1. Answer:

    3x – 39

    Step-by-step explanation:

    a(b(x)) = 3b(x) – 12

    = 3(x – 9) – 12

    = 3x – 27 – 12

    = 3x – 39

  2. The value of a[b(x)] is 3x-39

    Explanation:

    Given that the functions a(x)=3x-12 and b(x)=x-9

    We need to determine the value of a[b(x)]

    The value of a[b(x)] can be determined by substituting x=x-9 in the function  a(x)=3x-12

    Thus, we have,

    a[b(x)]=a(x-9)

    Let us substitute the value x=x-9 in the function a(x)=3x-12

    Substituting x=x-9 in the function a(x)=3x-12 , we get,

    a[b(x)]=3(x-9)-12

    Multiplying the terms, we get,

    a[b(x)]=3x-27-12

    Adding the like terms, we have,

    a[b(x)]=3x-39

    Thus, the value of a[b(x)] is 3x-39

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