## GRAVITATION The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocit

Question

GRAVITATION The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation h(t) = –16t2 + 60t. At what times will the object be at a height of 56 feet?

A. 14 s, 6 s

B. 1.75 s, 2 s

C. 8 s, 1 s

D. −1.75 s, −2 s

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2021-11-21T12:23:23+00:00
2021-11-21T12:23:23+00:00 1 Answer
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## Answers ( )

## Option B

## At 2 second and 1.75 second, the object be at a height of 56 feet

Solution:Given that,

The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:At what times will the object be at a height of 56 feetSubstitute h = 56Solve the above equation by quadratic formula

Thus, at 2 second and 1.75 second, the object be at a height of 56 feet