he width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the resulting re

Question

he width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the resulting rectangle is 60 square feet. What is the area of the original rectangle?

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Amara 6 days 2022-01-12T19:07:39+00:00 1 Answer 0 views 0

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    2022-01-12T19:08:41+00:00

    The original area of the rectangle is 35ft^{2}

    Explanation:

    width = x

    length = x + 2

    area of the rectangle = x (x+2)

    length = x + 2 + 5 = x+7

    60 = (x+7) (x)\\60=x^{2} + 7x\\x^{2}  + 7x - 60 =0\\

    Solving this equation, we get

    x =5ft

    So, original  width = 5ft

    original length = 5+2ft = 7ft

    Thus, original area of the rectangle = 5 X 7ft = 35ft^{2}

    Therefore, the original area of the rectangle is 35ft^{2}

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45:7+7-4:2-5:5*4+35:2 =? ( )