help please ! will mark brainliest Dr. Hamilton took an alloy containing 40% silver and mixed it with an alloy containing

Question

help please ! will mark brainliest
Dr. Hamilton took an alloy containing 40%
silver and mixed it with an alloy containing
60% silver to get an 80-ounce alloy con-
taining 45% silver. How many ounces of
the 40% alloy did he use?

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Arianna 3 weeks 2021-09-28T06:05:18+00:00 2 Answers 0

Answers ( )

    0
    2021-09-28T06:06:23+00:00

    Answer: he used 60 ounces of

    the 40% alloy.

    Step-by-step explanation:

    Let x represent the number of ounces of alloy containing 40%

    silver that was used.

    Let y represent the number of ounces of alloy containing 60%

    silver that was used.

    The weight of the alloy made is 80 ounces. It means that

    x + y = 80

    The amount of silver contained in the first alloy is 40/100 × x = 0.4x

    The amount of silver contained in the second alloy is 60/100 × x = 0.6x

    The amount of silver contained in the mixture is 45/100 × 80 = 36

    Therefore,

    0.4x + 0.6y = 36- – – – – – – – – – – – -1

    Substituting x = 80 – y into equation 1, it becomes

    0.4(80 – y) + 0.6y = 36

    32 – 0.4y + 0.6y = 36

    – 0.4y + 0.6y = 36 – 32

    0.2y = 4

    y = 4/0.2

    y = 20

    x = 80 – 20

    x = 60

    0
    2021-09-28T06:07:12+00:00

    He used about 60% of alloy

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