## Here are the equations of five straight lines. Line A. y + 3x = 4 Line B. 2y = x + 1 Line C. y + 2x = 3 Line

Question

Here are the equations of five straight lines.
Line A. y + 3x = 4
Line B. 2y = x + 1
Line C. y + 2x = 3
Line D. y = 4x – 2
Line E. 2y = 2x – 1
Two of these lines are perpendicular.
Write down the two perpendicular lines.

in progress 0
3 months 2022-02-15T07:24:11+00:00 1 Answer 0 views 0

Step-by-step explanation:

perpendicular lines have negative reciprocal slopes. So we will put each equation in y = mx + b form, and compare the slopes. The slopes, in y = mx + b form, are in the m position.

Line A : y + 3x = 4….y = -3x + 4…..slope is -3

Line B: 2y = x + 1…..y = 1/2x + 1/2…..slope is 1/2

Line C : y + 2x = 3…..y = -2x + 3……slope is -2

Line D: y = 4x – 2…..slope = 4

Line E: 2y = 2x- 1……y = x – 1/2…..slope is 1

take a look at Line B. it has a slope of 1/2…..to find the negative reciprocal, all that means is flip the slope and change the sign.

slope 1/2……flip it…..2/1…..change the sign…-2/1 or just -2.

this means that a line perpendicular to this one will have a slope of -2….and thats the slope Line C has.

so line B and line C are perpendicular <=== because there slopes are negative reciprocals of each other…..slope 1/2 and slope -2