## Hurry 50 points for correct answer Solve the equation. Identify any extraneous situations. x=√6x+7 1 is a solution t

Question

Hurry 50 points for correct answer
Solve the equation. Identify any extraneous situations.
x=√6x+7

1 is a solution to the original equation. The value –7 is an extraneous solution.

7 is a solution to the original equation. The value –1 is an extraneous solution.

7 and –1 are solutions.

7 and 1 are both extraneous solutions.

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2 hours 2021-10-14T13:50:34+00:00 2 Answers 0

1. Answer: “7 is a solution to the original equation. The value –1 is an extraneous solution.”

Step-by-step explanation:

2. Answer: “7 is a solution to the original equation. The value –1 is an extraneous solution.”

Step-by-step explanation:

The equation can be solved by squaring both sides: We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation: The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is “7 is a solution to the original equation. The value –1 is an extraneous solution.”