I need help solving systems of linear equations by substitution. The problem is {4x-3=5 -8x+6y=-10

Question

I need help solving systems of linear equations by substitution.
The problem is
{4x-3=5
-8x+6y=-10

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Sarah 2 weeks 2021-09-08T09:12:53+00:00 1 Answer 0

Answers ( )

    0
    2021-09-08T09:14:16+00:00

    Answer:

    x = 2 and y = 1

    Step-by-step explanation:

    4x = 5+3

    4x = 8

    x = 8/4

    x= 2

    so substitute the value of x in the second problem

    -8(2) + 6y = -10

    -16 + 6y = -10

    6y= -10 + 16

    6y= 6

    y= 6/6

    y = 1

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45:7+7-4:2-5:5*4+35:2 =? ( )