## I will give 30 points to whoever answers this correctly and within 5-10 mins. The perimeter of a rectangular room Is 24 feet. Tw

I will give 30 points to whoever answers this correctly and within 5-10 mins.

The perimeter of a rectangular room Is 24 feet. Twice the length decreased by three times the width is 4 feet. What are the dimensions of the room?

Question 1

Reread the question. What dimensions are you solving for?

Group of answer choices

perimeter

length

width

diagonals

Area

Question 2

Choose variables and write a system of equations.

Use elimination method to add or subtract equations.

Substitute the solution into one of the original equations and solve for the remaining variable.

Check answer by substituting solution into original equations.

Question 3

Interpret the answer in terms of the original question.

The length of the room is___feet and the width of the room is_____feet.

## Answers ( )

Answer:1)The dimensions you are solving forlength of the rectangular room

width of the rectangular room

2)Now let the length be L and the width be w thenthe perimeter is 2L+2W

2L+ 2W = 24——————————(1)Also, “Twice the length decreased by three times the width is 4 feet” can be written as

2L – 3W = 4————————————-(2)Solving (1) and (2) by elimination method, by subtraction

2L+ 2W = 242L – 3W = 4(-) (-) (-)—————————-

0L +5W = 20

—————————–

5W = 20

W = 4——————————————–(3)Now by substitution method,substituting (3) in(1)

2L+ 2(4) = 242L + 8 = 24

2L = 24 -8

2L = 16

L = 8Substituting in the original equation and rechecking the perimeter=2(8) + 2(4)

=16 + 8

= 24

Thus the found dimensions are correct

3)The length of the room is8 feetand the width of the room is4 feet.