## If 2.70 L of propane at 24°C and 57.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

Question

If 2.70 L of propane at 24°C and 57.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

Stoichiometry

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2 months 2021-10-05T20:44:41+00:00 1 Answer 0 views 0

Step-by-step explanation:

Data

Volume = 2.7 L

Temperature = 24°C

Pressure = 57.2 kPa

moles of CO₂ = ?

Process

1.- Calculate the moles of Propane, use the ideal gas formula

PV = nRT

n = PV / RT

– Convert temperature to °K

°K = 273 + 24 = 297

– Convert pressure to atm

1 atm —————– 101325 Pa

x       ——————  57200 Pa

x = (57200 x 1)/101325

x = 0.56 atm

– Substitution

n = (0.56)(2.7) / (0.082)(297)

– Simplification

n = 1.512 / 24.354

– Result

n = 0.062 moles

2.- Balanced the chemical reaction

C₃H₈  +  5O₂   ⇒    3CO₂  +  4H₂O

3.- Calculate the moles of Carbon dioxide

1 moles of C₃H₈  —————— 3 moles of CO₂

0.062 moles      ——————-   x

x = (0.062 x 3) / 1

x = 0.186 moles