If 2.70 L of propane at 24°C and 57.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

Question

If 2.70 L of propane at 24°C and 57.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produced?

Stoichiometry

in progress 0
Isabelle 2 months 2021-10-05T20:44:41+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-05T20:46:03+00:00

    Answer:

    The answer to your question is 0.186 moles  of CO₂

    Step-by-step explanation:

    Data

    Volume = 2.7 L

    Temperature = 24°C

    Pressure = 57.2 kPa

    moles of CO₂ = ?

    Process

    1.- Calculate the moles of Propane, use the ideal gas formula

              PV = nRT

              n = PV / RT

    – Convert temperature to °K          

      °K = 273 + 24 = 297

    – Convert pressure to atm

              1 atm —————– 101325 Pa

              x       ——————  57200 Pa

              x = (57200 x 1)/101325

              x = 0.56 atm

    – Substitution

             n = (0.56)(2.7) / (0.082)(297)

    – Simplification  

              n = 1.512 / 24.354

    – Result

              n = 0.062 moles

    2.- Balanced the chemical reaction

                      C₃H₈  +  5O₂   ⇒    3CO₂  +  4H₂O

    3.- Calculate the moles of Carbon dioxide

                     1 moles of C₃H₈  —————— 3 moles of CO₂

                     0.062 moles      ——————-   x

                     x = (0.062 x 3) / 1

                    x = 0.186 moles  

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )