If a polynomial function f(x) has roots 8, 1, and 6i, what must also be a root of f(x)?

Question

If a polynomial function f(x) has roots 8, 1, and 6i, what must also be a root of f(x)?

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Parker 2 weeks 2021-09-08T00:56:33+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T00:57:35+00:00

    Answer:

    Step-by-step explanation:

    complex and irrational roots always occur in pairs.

    so -6i is the second root.

    0
    2021-09-08T00:58:23+00:00

    Answer:

    –6i

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )