If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

Question

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

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Bella 1 month 2021-09-08T01:35:00+00:00 1 Answer 0

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    2021-09-08T01:36:23+00:00

    ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

    Step-by-step explanation:

    Here we have , ab= 8 & a^2+b^2=16 i.e. ab = 8  and a^{2} + b^{2} = 16 .

    We need to find value of (a+b)^2 i.e. (a+b)^{2} :

    It’s and identity and we know that ( a+b )^{2} = a^{2} +b^{2} +2ab

    ( a+b )^{2} = a^{2} +b^{2} +2ab

    ( a+b )^{2} = (a^{2} +b^{2}) +2(ab)

    ( a+b )^{2} = (16) +2(8)

    ( a+b )^{2} = (16) +(16)

    ( a+b )^{2} = 32

    ab = 8 & a^{2} + b^{2} = 16 so , ( a+b )^{2} = 32 .

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