## If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained by multiplyi

Question

If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the result. Find V as a linear function of t, and use this function to evaluate V(7.8), the velocity of the object at time t = 7.8 seconds.
A. V(7.8) = 257.6 ft per sec

B. V(7.8) = 260.9 ft per sec

C. V(7.8) = 259.6 ft per sec

D. V(7.8) = 258.9 ft per sec

E. None of these

in progress 0
4 months 2022-01-21T05:30:59+00:00 1 Answer 0 views 0

259.6 ft/sec

Step-by-step explanation:

it is a universal standard that acceleration due to gravity is 32ft/sec^2.

Now it can be verified by equation,

V(f) = V(i)+at (1st equation of motion derived by Newton’s three laws of motion)

where,

V(f) is final velocity

V(i) is initial velocity

a is acceleration which is constant and have value 32ft/sec^2

t is time which is given as 7.8 seconds

In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.

So,

V(f) = 0 +(32) (7.8)

V(f) = 249.6 ft/sec

Now the condition is given that you have to add a constant 10 to the answer.

so, V(f) = 249.6 + 10

V(f) = 259.6 ft/sec