If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained by multiplyi

Question

If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the result. Find V as a linear function of t, and use this function to evaluate V(7.8), the velocity of the object at time t = 7.8 seconds.
A. V(7.8) = 257.6 ft per sec

B. V(7.8) = 260.9 ft per sec

C. V(7.8) = 259.6 ft per sec

D. V(7.8) = 258.9 ft per sec

E. None of these

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Kaylee 4 months 2022-01-21T05:30:59+00:00 1 Answer 0 views 0

Answers ( )

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    2022-01-21T05:32:01+00:00

    Answer:

    259.6 ft/sec

    Step-by-step explanation:

    it is a universal standard that acceleration due to gravity is 32ft/sec^2.

    Now it can be verified by equation,

    V(f) = V(i)+at (1st equation of motion derived by Newton’s three laws of motion)

    where,

    V(f) is final velocity

    V(i) is initial velocity

    a is acceleration which is constant and have value 32ft/sec^2

    t is time which is given as 7.8 seconds

    In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.

    So,

    V(f) = 0 +(32) (7.8)

    V(f) = 249.6 ft/sec

    Now the condition is given that you have to add a constant 10 to the answer.

    so, V(f) = 249.6 + 10

          V(f) = 259.6 ft/sec

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