We will think as follows. Recall that at first, he chooses 3 books. Then, we want to see in how many ways he can arrange this books. For the first book, he has 3 options, for the second one 2 and for the third 1. Then, the total number of ways in which he can arrange 3 books is 3!. So we know that after choosing 3 books, he can arrange them in 3! ways. So, we want to check the total number of ways he can choose 3 books out of 12. That is given by the binomial coefficient [tex]\binom{12}{3}[/tex]. Then, the total number of ways of arranging 3 books is

## Answers ( )

Answer:1320

Step-by-step explanation:We will think as follows. Recall that at first, he chooses 3 books. Then, we want to see in how many ways he can arrange this books. For the first book, he has 3 options, for the second one 2 and for the third 1. Then, the total number of ways in which he can arrange 3 books is 3!. So we know that after choosing 3 books, he can arrange them in 3! ways. So, we want to check the total number of ways he can choose 3 books out of 12. That is given by the binomial coefficient [tex]\binom{12}{3}[/tex]. Then, the total number of ways of arranging 3 books is

[tex]\binom{12}{3}\cdot 3! = \frac{12!}{(12-3)! 3!}\cdot 3! = \frac{12!}{(12-3)!} = 1320[/tex]

Thus, he can arrange 3 books out of 12 in 1320 different ways