if the quadratic equation x^2 + 18x +74=0 is rewritten in the form (x-p)^2 = Q what is the value of Q? A) -155 B) -7

Question

if the quadratic equation x^2 + 18x +74=0 is rewritten in the form (x-p)^2 = Q what is the value of Q?

A) -155

B) -74

C) 7

D) 9

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Genesis 1 week 2021-11-16T03:58:15+00:00 1 Answer 0 views 0

Answers ( )

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    2021-11-16T04:00:07+00:00

    The value of Q “option C) 7” is correct option.

    Step-by-step explanation:

    The given quadratic equation:

    x^2 - 18x +74=0

    To find, the value of Q = ?

    x^2 - 18x +74=0

    Adding both sides 81, we get

    x^2 - 18x +81+74=81

    x^2 – 2(x)8 + 9^2 = 81 – 74

    Using the algebraic identity,

    (a-b)^{2} =a^{2} +b^{2} -2ab

    (x-9)^{2} =7 is the form of  (x-p)^2 = Q

    Here, P = 9 and Q = 7

    Thus, the value of Q “option C) 7” is correct option.

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45:7+7-4:2-5:5*4+35:2 =? ( )