## Ben wants to try a new restaurant for dinner. His online search resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3<

Question

Ben wants to try a new restaurant for dinner. His online search

resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3

new 5-star restaurants. If he were to choose a restaurant at random,

what is the probability that he chooses a 5-star restaurant?

Select one:

33%

20%

47%

3%

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Math
3 weeks
2021-10-08T02:11:21+00:00
2021-10-08T02:11:21+00:00 2 Answers
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## Answers ( )

It would be about 3% I got this because you first had to multiply the results by the amount of stars they had so like 7*3 is 21 and so on if you did this to all the pairs you would get 56 now divide 56 by the amount of restaurants 7+5+3 which is 15 so 56 divided by 15 is about 3%

Ben found:

7 ⭐️⭐️⭐️ restaurants

5 ⭐️⭐️⭐️⭐️ restaurants

3 ⭐️⭐️⭐️⭐️⭐️ restaurants

A total of 15 restaurants

Out of the 15 restaurants, 3 will be 5-star. So, 3/15, reduces to 1/5 and 1/5 as a percentage is 20%

Ben’s probability of choosing a 5-star restaurant at random is 20%