In a certain Algebra 2 class of 28 students, 14 of them play basketball and 7 of them play baseball. There are 2 students who play bot

Question

In a certain Algebra 2 class of 28 students, 14 of them play basketball and 7 of them
play baseball. There are 2 students who play both sports. What is the probability that
a student chosen randomly from the class plays basketball or baseball?

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Lydia 2 weeks 2021-09-15T05:54:39+00:00 1 Answer 0

Answers ( )

    0
    2021-09-15T05:55:52+00:00

    Answer:

    p(student plays basketball or baseball) = \frac{19}{28}

    Step-by-step explanation:

    p(student plays basketball)= \frac{14}{28\\}

    p(student plays baseball)= \frac{7}{28}

    2 students play both sports= \frac{2}{28}

    \frac{14}{28} +\frac{7}{28} -\frac{2}{28} =\frac{19}{28}

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45:7+7-4:2-5:5*4+35:2 =? ( )