In △CDE , CD=12 , DE=5 , and m∠E=83∘ . What is m∠D to the nearest tenth of a degree?

Question

In △CDE , CD=12 , DE=5 , and m∠E=83∘ .

What is m∠D to the nearest tenth of a degree?

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Faith 1 week 2021-09-14T05:11:09+00:00 1 Answer 0

Answers ( )

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    2021-09-14T05:12:19+00:00

    Answer:

    As law of sin:

    CD/sinE = DE/sinC

    Then

    12/sin83 = 5/sinC

    Then

    sinC = 5*sin83/12 = 0.413

    Then

    C = arcsin(0.413) = ~24.4 deg

    Then

    D = 180-C-E = 180-83-24.4 = ~72.6

    Hope this help, bro!

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