In the year 2008, a person bought a new car for $17000. For each consecutive year after that, the value of the car depreciated by 8%. How mu

Question

In the year 2008, a person bought a new car for $17000. For each consecutive year after that, the value of the car depreciated by 8%. How much would the car be worth in the year 2011, to the nearest hundred dollars?

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Madeline 2 weeks 2021-11-20T19:11:15+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-20T19:12:16+00:00

    Step-by-step explanation:

    This is a simple exponential equation:

    cost=17000*0.92^(years after 2008)

    so since 2011-2008 yields 3

    it will be 3 years after 2008, so

    cost = 17000 * 0.92^3

    $13,237.69

    0
    2021-11-20T19:12:31+00:00

    Answer:

    $ 17000 * 0.92 ^ 3 = $ 13237.696

    to the nearest hundred it’s $ 13000

    i hope yoe start to see the pattern here

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