Is the point (4,-1) on the circle with a center at (0,2) and containing the point (0,-3)? (please show work)

Question

Is the point (4,-1) on the circle with a center at (0,2) and containing the point (0,-3)? (please show work)

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Melody 3 months 2022-02-15T19:55:09+00:00 1 Answer 0 views 0

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    2022-02-15T19:56:44+00:00

    Step-by-step explanation:

    If the point is on the circle, then the distance from the center will be the same as the distance between (0,-3) and the center.

    The distances are:

    d = √((x₂ − x₁)² + (y₂ − y₁)²)

    d = √((0 − 0)² + (-3 − 2)²)

    d = √(0² + (-5)²)

    d = 5

    d = √((x₂ − x₁)² + (y₂ − y₁)²)

    d = √((4 − 0)² + (-1 − 2)²)

    d = √(4² + (-3)²)

    d = 5

    The distances are the same.  So yes, the point is on the circle.

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