## Is the point (4,-1) on the circle with a center at (0,2) and containing the point (0,-3)? (please show work)

Question

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## Answers ( )

Step-by-step explanation:If the point is on the circle, then the distance from the center will be the same as the distance between (0,-3) and the center.

The distances are:

d = √((x₂ − x₁)² + (y₂ − y₁)²)

d = √((0 − 0)² + (-3 − 2)²)

d = √(0² + (-5)²)

d = 5

d = √((x₂ − x₁)² + (y₂ − y₁)²)

d = √((4 − 0)² + (-1 − 2)²)

d = √(4² + (-3)²)

d = 5

The distances are the same. So yes, the point is on the circle.