## How many 3 number combinations are possible if you can’t repeat the numbers? The numbers range from 0-39

Question

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## Answers ( )

Answer: 49600Step-by-step explanation: There are 40 ways to choose the first numberand there are 40 ways to choose the second number.Now we take some examples to determine how many choices there are forthe third numberIf the second number is 23, then the 3rd number cannot be any of these9 numbers 19,20,21,22,23,24,25,26,or 27, since they are not at least 5numbers away from 23. Same for all other 40 second numbers.Let’s look at a second example which includes some on both sides of 0.If second number is 2, we couldn’t choose any of the 9 numbers 38,39,0,1,2,3,4,5,6.So thats 40-9 or 31 choices for the 3rd number.Answer 40*40*31 = 49600 ways.