Jason went to the post office and bought both 41-cent stamps and 26-cent postcards and spent $10.28. The number of stamps was 4 more than tw

Question

Jason went to the post office and bought both 41-cent stamps and 26-cent postcards and spent $10.28. The number of stamps was 4 more than twice the number of postcards. How many of each did he buy?

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Ruby 1 month 2021-10-20T20:44:57+00:00 1 Answer 0 views 0

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    2021-10-20T20:46:55+00:00

    Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.

    Solution:

    Let stamps be s and postcards be p

    Given that,

    The number of stamps was 4 more than twice the number of postcards

    s = 4 + 2p ——– eqn 1

    Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28

    41 cent = $ 0.41

    26 cent = $ 0.26

    Therefore,

    s \times 0.41 + p \times 0.26 = 10.28

    0.41s + 0.26p = 10.28 ——— eqn 2

    Substitute eqn 1 in eqn 2

    0.41(4 + 2p) + 0.26p = 10.28

    1.64 + 0.82p + 0.26p = 10.28

    1.08p = 10.28 – 1.64

    1.08p = 8.64

    Divide both sides by 1.08

    p = 8

    Substitute p = 8 in eqn 1

    s = 4 + 2(8)

    s = 4 + 16

    s = 20

    Thus Jason bought 20 stamps and 8 post cards

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