Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 minutes, what

Question

Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 minutes, what is the probability her first two pieces will both be jelly treats?

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Adalyn 1 week 2021-09-08T01:14:28+00:00 2 Answers 0

Answers ( )

    0
    2021-09-08T01:15:58+00:00

    Answer:

    18.95%

    Step-by-step explanation:

    In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

    We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:

    9/20  

    And the second event, with one less in each, would be:

    8/19

    The final probability then:

    9/20 * 8/19 = 0.1895

    So the probability of this happening is 18.95%

    0
    2021-09-08T01:16:12+00:00

    Answer:

    18/95

    Step-by-step explanation:

    Given data

    2 mint sticks,

    9 jelly treats, and

    9 fruit tart chews.

    Sample space = {2+9+9} = 20

    N/B this is done without replacement since the candy are eaten Hence after each selection the candy and the sample size reduces

    1.The probability of eating the first jelly treat = 9/20

    2.The probability of eating the first jelly treat = 8/19

    Hence the probability of her first two pieces will both

    be jelly i= 9/20*8/19= 72/380

    = 18/95

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