Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample

Question

Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below.H0:μ=8.2 seconds; Ha:μ<8.2 secondsα=0.04 (significance level)z0=−1.75p=0.0401Select the correct answer below:Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.Reject the null hypothesis because the value of z is negative.Reject the null hypothesis because |−1.75|>0.04.Do not reject the null hypothesis because |−1.75|>0.04.

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Audrey 6 days 2021-10-09T20:25:24+00:00 1 Answer 0

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    2021-10-09T20:26:37+00:00

    Answer:

    The data does not provide sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds.

    Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level.

    Step-by-step explanation:

    Null hypothesis (H0): mu = 8.2 seconds

    Alternate hypothesis (Ha): mu < 8.2 seconds

    Significance level = 0.04

    p-value = 0.0401

    Using the p-value approach for testing hypothesis, do not reject H0 because the p-value 0.0401 is greater than the significance level 0.04.

    There is not sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds.

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45:7+7-4:2-5:5*4+35:2 =? ( )