## Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample

Question

Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below.H0:μ=8.2 seconds; Ha:μ<8.2 secondsα=0.04 (significance level)z0=−1.75p=0.0401Select the correct answer below:Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04.Reject the null hypothesis because the value of z is negative.Reject the null hypothesis because |−1.75|>0.04.Do not reject the null hypothesis because |−1.75|>0.04.

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1 month 2021-10-09T20:25:24+00:00 1 Answer 0 views 0

The data does not provide sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds.

Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level.

Step-by-step explanation:

Null hypothesis (H0): mu = 8.2 seconds

Alternate hypothesis (Ha): mu < 8.2 seconds

Significance level = 0.04

p-value = 0.0401

Using the p-value approach for testing hypothesis, do not reject H0 because the p-value 0.0401 is greater than the significance level 0.04.

There is not sufficient evidence to conclude that Kenneth’s mean stacking time is less than 8.2 seconds.