Let ABCDEF be a convex hexagon, and denote by P, Q, R, S, T, U the midpoints of the sides AB, BC, CD, DE, EF, FA respectively. Suppose that

Question

Let ABCDEF be a convex hexagon, and denote by P, Q, R, S, T, U the midpoints of the sides AB, BC, CD, DE, EF, FA respectively. Suppose that the areas of the triangles ABR, BCS, CDT, DEU, EFP and FAQ are 12, 34, 56, 12, 34 and 56 respectively.Find the area of hexagon?

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Elliana 2 months 2021-09-23T23:51:13+00:00 1 Answer 0 views 0

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    2021-09-23T23:52:34+00:00

    Answer:

    The answer to the question is;

    The area of hexagon is 136.

    Step-by-step explanation:

    We have area ABR = 0.5 (ABC+ABD) since R = midpoint of segment CD

    Similarly we have area BCS = 0.5 ( BCD+BCE)

    also area CDT = 0.5(CDE+CDF)

    DEU = 0.5(DEF+DEA)

    EFP = 0.5(EFA+EFB) and

    FAQ = 0.5(FAB+FAC)

    However 0.5 (ABC+ABD) + 0.5 ( BCD+BCE)+0.5(CDE+CDF)+0.5(DEF+DEA)+

                       0.5(EFA+EFB) + 0.5(FAB+FAC) =  0.5*6*0.5 * Area of a regular hexagon

    = 3/2×area of the hexagon = 12+34+56+12+34+56 = 204

    Area of the hexagon = 2/3*204= 136

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45:7+7-4:2-5:5*4+35:2 =? ( )