Line K has a slope of 3. Line J is perpendicular to like K and passes through the point (3,8). Type the equation of the line in y=Mx+b

Question

Line K has a slope of 3. Line J is perpendicular to like K and passes through the point (3,8). Type the equation of the line in y=Mx+b

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1 week 2022-01-08T19:16:32+00:00 1 Answer 0 views 0

1. I’m assuming you are finding the equation of the line of Line J

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 –> (0, y) or the point where the line crosses through the y-axis]

For lines to be perpendicular, the slopes have to be negative reciprocals of each other. (basically changing the sign (+/-) and flipping the fraction/switching the numerator and the denominator)

For example:

slope = 2 or Perpendicular line’s slope = [changed sign from + to -, and flipped the fraction]

slope = Perpendicular line’s slope = [changed sign from – to +, and flipped the fraction]

Since you know the slope is 3, the perpendicular line’s slope is .  Plug this into the equation

y = mx + b To find b, plug in the point (3, 8) 8 = -1 + b    Add 1 on both sides to get “b” by itself

8 + 1 = -1 + 1 + b

9 = b 